Rút gọn phân thức P=\(\frac{\left(1^4+4\right)\left(5^4 +4\right)\left(9^4+4\right)...\left(21^4+4\right)}{\left(3^4+4\right)\left(7^4+4\right)\left(11^4+4\right)...\left(23^4+4\right)}\)
\(P=\left(\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+4\right)....\left(21^4+4\right)}{\left(3^4+4\right)\left(7^4+4\right)\left(11^4+4\right).....\left(23^4+4\right)}\right)\). Rút gọn biểu thức
rút gọn biểu thức
P=\(\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+4\right)...\left(21^4+4\right)}{\left(3^4+4\right)\left(7^4+4\right)\left(11^4+4\right)...\left(23^4+4\right)}\)
rút gọn biểu thức P=\(\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+1\right)...\left(21^4+1\right)}{\left(3^4+1\right)\left(7^4+1\right)\left(11^4+1\right)...\left(23^4+1\right)}\)
Rút gọn biểu thức P=\(\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+4\right)...\left(21^4+4\right)}{\left(3^4+1\right)\left(7^4+1\right)\left(11^4+1\right)...\left(23^4+1\right)}\)
rút gọn các biểu thức ( viết kết quả dưới dạng phân số )
\(B=\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+4\right)...\left(21^4+4\right)}{\left(3^4+4\right)\left(7^4+4\right)\left(11^4+4\right)...\left(23^4+4\right)}\)
rút gọn bieu thuc P=\(\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+1\right)...\left(21^4+1\right)}{\left(3^4+1\right)\left(7^4+1\right)\left(11^4+1\right)...\left(23^4+1\right)}\)
rút gọn biểu thức:
\(P=\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+4\right).....\left(21^4+4\right)}{\left(3^4+4\right)\left(7^4+4\right)\left(11^4+4\right)....\left(23^4+4\right)}\)
Rút gọn biểu thức P=\(\frac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+1\right)...\left(21^4+1\right)}{\left(3^4+1\right)\left(7^4+1\right)\left(11^4+1\right)...\left(23^4+1\right)}\)
Giúp e vs mn ơi
Rút gọn biểu thức :
\(P=\dfrac{\left(1^4+4\right)\left(5^4+4\right)\left(9^4+4\right)....\left(21^4+4\right)}{\left(3^4+4\right)\left(7^4+4\right)\left(11^4+4\right)....\left(23^4+4\right)^{ }}\)
ta co dang tong quat cho tu so la : n^4+4=(n^2+2)^2=(n^2+2n+2)(n^2-2n+2)=[(n-1)^2+1][(n+1)^2+1]
Nen A=(0+1)(2^2+1)/(2^2+1)(4^2+1) . (4^2+1)(6^2+1)/(6^2+1)(8^2+1) .........(20^2+1)(22^2+1)/(22^2+1)(24^2+1) = 1/24^2+1=1/577